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10=154-10t-16t^2
We move all terms to the left:
10-(154-10t-16t^2)=0
We get rid of parentheses
16t^2+10t-154+10=0
We add all the numbers together, and all the variables
16t^2+10t-144=0
a = 16; b = 10; c = -144;
Δ = b2-4ac
Δ = 102-4·16·(-144)
Δ = 9316
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9316}=\sqrt{4*2329}=\sqrt{4}*\sqrt{2329}=2\sqrt{2329}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{2329}}{2*16}=\frac{-10-2\sqrt{2329}}{32} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{2329}}{2*16}=\frac{-10+2\sqrt{2329}}{32} $
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