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10=11+8/x-x
We move all terms to the left:
10-(11+8/x-x)=0
Domain of the equation: x-x)!=0We add all the numbers together, and all the variables
x∈R
-(-1x+8/x+11)+10=0
We get rid of parentheses
1x-8/x-11+10=0
We multiply all the terms by the denominator
1x*x-11*x+10*x-8=0
We add all the numbers together, and all the variables
-1x+1x*x-8=0
Wy multiply elements
x^2-1x-8=0
a = 1; b = -1; c = -8;
Δ = b2-4ac
Δ = -12-4·1·(-8)
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{33}}{2*1}=\frac{1-\sqrt{33}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{33}}{2*1}=\frac{1+\sqrt{33}}{2} $
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