10=-5(1-3a)-6(5+5a)

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Solution for 10=-5(1-3a)-6(5+5a) equation: 



10=-5(1-3a)-6(5+5a)

We move all terms to the left:

10-(-5(1-3a)-6(5+5a))=0

We add all the numbers together, and all the variables

-(-5(-3a+1)-6(5a+5))+10=0



We calculate terms in parentheses: -(-5(-3a+1)-6(5a+5)), so:

-5(-3a+1)-6(5a+5)

We multiply parentheses

15a-30a-5-30

We add all the numbers together, and all the variables

-15a-35

Back to the equation:

-(-15a-35)



We get rid of parentheses

15a+35+10=0

We add all the numbers together, and all the variables

15a+45=0

We move all terms containing a to the left, all other terms to the right

15a=-45

a=-45/15

a=-3

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