10=-12+7(j+10)

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Solution for 10=-12+7(j+10) equation: 



10=-12+7(j+10)

We move all terms to the left:

10-(-12+7(j+10))=0



We calculate terms in parentheses: -(-12+7(j+10)), so:

-12+7(j+10)

determiningTheFunctionDomain
7(j+10)-12

We multiply parentheses

7j+70-12

We add all the numbers together, and all the variables

7j+58

Back to the equation:

-(7j+58)



We get rid of parentheses

-7j-58+10=0

We add all the numbers together, and all the variables

-7j-48=0

We move all terms containing j to the left, all other terms to the right

-7j=48

j=48/-7

j=-6+6/7

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