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10=(9/3)*q
We move all terms to the left:
10-((9/3)*q)=0
Domain of the equation: 3)*q)!=0We add all the numbers together, and all the variables
q!=0/1
q!=0
q∈R
-(3*q)+10=0
We get rid of parentheses
-3*q+10=0
We add all the numbers together, and all the variables
-3q+10=0
We move all terms containing q to the left, all other terms to the right
-3q=-10
q=-10/-3
q=3+1/3
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