10=(-(2/3))(4x+5)

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Solution for 10=(-(2/3))(4x+5) equation: 



10=(-(2/3))(4x+5)

We move all terms to the left:

10-((-(2/3))(4x+5))=0



Domain of the equation: 3))(4x+5))!=0

x∈R



We add all the numbers together, and all the variables

-((-(+2/3))(4x+5))+10=0

We multiply all the terms by the denominator


-((-(+2+10*3))(4x+5))=0



We calculate terms in parentheses: -((-(+2+10*3))(4x+5)), so:

(-(+2+10*3))(4x+5)

We add all the numbers together, and all the variables

(-32)(4x+5)

We multiply parentheses ..

(-128x-160)

We get rid of parentheses

-128x-160

Back to the equation:

-(-128x-160)



We get rid of parentheses

128x+160=0

We move all terms containing x to the left, all other terms to the right

128x=-160

x=-160/128

x=-1+1/4

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