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108=(24-x)x
We move all terms to the left:
108-((24-x)x)=0
We add all the numbers together, and all the variables
-((-1x+24)x)+108=0
We calculate terms in parentheses: -((-1x+24)x), so:We get rid of parentheses
(-1x+24)x
We multiply parentheses
-1x^2+24x
Back to the equation:
-(-1x^2+24x)
1x^2-24x+108=0
We add all the numbers together, and all the variables
x^2-24x+108=0
a = 1; b = -24; c = +108;
Δ = b2-4ac
Δ = -242-4·1·108
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-12}{2*1}=\frac{12}{2} =6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+12}{2*1}=\frac{36}{2} =18 $
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