108+(2x)=(4x+80)

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Solution for 108+(2x)=(4x+80) equation: 



108+(2x)=(4x+80)

We move all terms to the left:

108+(2x)-((4x+80))=0



We calculate terms in parentheses: -((4x+80)), so:

(4x+80)

We get rid of parentheses

4x+80

Back to the equation:

-(4x+80)



We get rid of parentheses

2x-4x-80+108=0

We add all the numbers together, and all the variables

-2x+28=0

We move all terms containing x to the left, all other terms to the right

-2x=-28

x=-28/-2

x=+14

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