105=(3y+7)/2+y+(10y-11)

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Solution for 105=(3y+7)/2+y+(10y-11) equation: 



105=(3y+7)/2+y+(10y-11)

We move all terms to the left:

105-((3y+7)/2+y+(10y-11))=0



Domain of the equation: 2+y+(10y-11))!=0

We move all terms containing y to the left, all other terms to the right

y+(10y-11))!=-2

y∈R



We multiply all the terms by the denominator


-((3y+7)+105*2+y+(10y-11))=0



We calculate terms in parentheses: -((3y+7)+105*2+y+(10y-11)), so:

(3y+7)+105*2+y+(10y-11)

determiningTheFunctionDomain
(3y+7)+y+(10y-11)+105*2

We add all the numbers together, and all the variables

y+(3y+7)+(10y-11)+210

We get rid of parentheses

y+3y+10y+7-11+210

We add all the numbers together, and all the variables

14y+206

Back to the equation:

-(14y+206)



We get rid of parentheses

-14y-206=0

We move all terms containing y to the left, all other terms to the right

-14y=206

y=206/-14

y=-14+5/7

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