103=3+3(4v+3)

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Solution for 103=3+3(4v+3) equation: 



103=3+3(4v+3)

We move all terms to the left:

103-(3+3(4v+3))=0



We calculate terms in parentheses: -(3+3(4v+3)), so:

3+3(4v+3)

determiningTheFunctionDomain
3(4v+3)+3

We multiply parentheses

12v+9+3

We add all the numbers together, and all the variables

12v+12

Back to the equation:

-(12v+12)



We get rid of parentheses

-12v-12+103=0

We add all the numbers together, and all the variables

-12v+91=0

We move all terms containing v to the left, all other terms to the right

-12v=-91

v=-91/-12

v=7+7/12

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