103=3(4n+4)-5

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Solution for 103=3(4n+4)-5 equation: 



103=3(4n+4)-5

We move all terms to the left:

103-(3(4n+4)-5)=0



We calculate terms in parentheses: -(3(4n+4)-5), so:

3(4n+4)-5

We multiply parentheses

12n+12-5

We add all the numbers together, and all the variables

12n+7

Back to the equation:

-(12n+7)



We get rid of parentheses

-12n-7+103=0

We add all the numbers together, and all the variables

-12n+96=0

We move all terms containing n to the left, all other terms to the right

-12n=-96

n=-96/-12

n=+8

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