101=2(6b+2)+1

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Solution for 101=2(6b+2)+1 equation: 



101=2(6b+2)+1

We move all terms to the left:

101-(2(6b+2)+1)=0



We calculate terms in parentheses: -(2(6b+2)+1), so:

2(6b+2)+1

We multiply parentheses

12b+4+1

We add all the numbers together, and all the variables

12b+5

Back to the equation:

-(12b+5)



We get rid of parentheses

-12b-5+101=0

We add all the numbers together, and all the variables

-12b+96=0

We move all terms containing b to the left, all other terms to the right

-12b=-96

b=-96/-12

b=+8

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