100x2-65x+10=0

Solution for 100x2-65x+10=0 equation:

100x^2-65x+10=0

a = 100; b = -65; c = +10;
Δ = b2-4ac
Δ = -652-4·100·10
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-65)-15}{2*100}=\frac{50}{200}
=1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-65)+15}{2*100}=\frac{80}{200}
=2/5
$