100x2-145=1

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Solution for 100x2-145=1 equation:



100x^2-145=1
We move all terms to the left:
100x^2-145-(1)=0
We add all the numbers together, and all the variables
100x^2-146=0
a = 100; b = 0; c = -146;
Δ = b2-4ac
Δ = 02-4·100·(-146)
Δ = 58400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{58400}=\sqrt{400*146}=\sqrt{400}*\sqrt{146}=20\sqrt{146}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{146}}{2*100}=\frac{0-20\sqrt{146}}{200} =-\frac{20\sqrt{146}}{200} =-\frac{\sqrt{146}}{10} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{146}}{2*100}=\frac{0+20\sqrt{146}}{200} =\frac{20\sqrt{146}}{200} =\frac{\sqrt{146}}{10} $

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