100x2+100x=96

Solution for 100x2+100x=96 equation:

100x^2+100x=96

We move all terms to the left:

100x^2+100x-(96)=0

a = 100; b = 100; c = -96;
Δ = b2-4ac
Δ = 1002-4·100·(-96)
Δ = 48400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{48400}=220$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-220}{2*100}=\frac{-320}{200}
=-1+3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+220}{2*100}=\frac{120}{200}
=3/5
$