100=b+(b+2b-45)

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Solution for 100=b+(b+2b-45) equation: 



100=b+(b+2b-45)

We move all terms to the left:

100-(b+(b+2b-45))=0

We add all the numbers together, and all the variables

-(b+(3b-45))+100=0



We calculate terms in parentheses: -(b+(3b-45)), so:

b+(3b-45)

We get rid of parentheses

b+3b-45

We add all the numbers together, and all the variables

4b-45

Back to the equation:

-(4b-45)



We get rid of parentheses

-4b+45+100=0

We add all the numbers together, and all the variables

-4b+145=0

We move all terms containing b to the left, all other terms to the right

-4b=-145

b=-145/-4

b=36+1/4

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