100=2.16*t^2-20.53*t+54

Simple and best practice solution for 100=2.16*t^2-20.53*t+54 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so dont hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for 100=2.16*t^2-20.53*t+54 equation:

100=2.16t^2-20.53t+54
We move all terms to the left:
100-(2.16t^2-20.53t+54)=0
We get rid of parentheses
-2.16t^2+20.53t-54+100=0
We add all the numbers together, and all the variables
-2.16t^2+20.53t+46=0
a = -2.16; b = 20.53; c = +46;Δ = b2-4acΔ = 20.532-4·(-2.16)·46Δ = 818.9209The delta value is higher than zero, so the equation has two solutionsWe use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20.53)-\sqrt{818.9209}}{2*-2.16}=\frac{-20.53-\sqrt{818.9209}}{-4.32}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20.53)+\sqrt{818.9209}}{2*-2.16}=\frac{-20.53+\sqrt{818.9209}}{-4.32}$

`