# 100=2.16*t^2

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## Solution for 100=2.16*t^2 equation:

100=2.16t^2
We move all terms to the left:
100-(2.16t^2)=0
We get rid of parentheses
-2.16t^2+100=0
a = -2.16; b = 0; c = +100;Δ = b2-4acΔ = 02-4·(-2.16)·100Δ = 864The delta value is higher than zero, so the equation has two solutionsWe use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$The end solution:
$\sqrt{\Delta}=\sqrt{864}=\sqrt{144*6}=\sqrt{144}*\sqrt{6}=12\sqrt{6}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{6}}{2*-2.16}=\frac{0-12\sqrt{6}}{-4.32} =-\frac{12\sqrt{6}}{-4.32} =-\frac{3\sqrt{6}}{-1.08}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{6}}{2*-2.16}=\frac{0+12\sqrt{6}}{-4.32} =\frac{12\sqrt{6}}{-4.32} =\frac{3\sqrt{6}}{-1.08}$

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