100=(4/5x)-20

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Solution for 100=(4/5x)-20 equation: 



100=(4/5x)-20

We move all terms to the left:

100-((4/5x)-20)=0



Domain of the equation: 5x)-20)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-((+4/5x)-20)+100=0

We multiply all the terms by the denominator


-((+4+100*5x)-20)=0



We calculate terms in parentheses: -((+4+100*5x)-20), so:

(+4+100*5x)-20

We add all the numbers together, and all the variables

(100*5x+4)-20

We get rid of parentheses

100*5x+4-20

We add all the numbers together, and all the variables

100*5x-16

Wy multiply elements

500x-16

Back to the equation:

-(500x-16)



We get rid of parentheses

-500x+16=0

We move all terms containing x to the left, all other terms to the right

-500x=-16

x=-16/-500

x=4/125

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