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1008=(2x+8)(x+6)
We move all terms to the left:
1008-((2x+8)(x+6))=0
We multiply parentheses ..
-((+2x^2+12x+8x+48))+1008=0
We calculate terms in parentheses: -((+2x^2+12x+8x+48)), so:We get rid of parentheses
(+2x^2+12x+8x+48)
We get rid of parentheses
2x^2+12x+8x+48
We add all the numbers together, and all the variables
2x^2+20x+48
Back to the equation:
-(2x^2+20x+48)
-2x^2-20x-48+1008=0
We add all the numbers together, and all the variables
-2x^2-20x+960=0
a = -2; b = -20; c = +960;
Δ = b2-4ac
Δ = -202-4·(-2)·960
Δ = 8080
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8080}=\sqrt{16*505}=\sqrt{16}*\sqrt{505}=4\sqrt{505}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-4\sqrt{505}}{2*-2}=\frac{20-4\sqrt{505}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+4\sqrt{505}}{2*-2}=\frac{20+4\sqrt{505}}{-4} $
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