1000(9x-10)=50(832+100x)

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Solution for 1000(9x-10)=50(832+100x) equation: 



1000(9x-10)=50(832+100x)

We move all terms to the left:

1000(9x-10)-(50(832+100x))=0

We add all the numbers together, and all the variables

1000(9x-10)-(50(100x+832))=0

We multiply parentheses

9000x-(50(100x+832))-10000=0



We calculate terms in parentheses: -(50(100x+832)), so:

50(100x+832)

We multiply parentheses

5000x+41600

Back to the equation:

-(5000x+41600)



We get rid of parentheses

9000x-5000x-41600-10000=0

We add all the numbers together, and all the variables

4000x-51600=0

We move all terms containing x to the left, all other terms to the right

4000x=51600

x=51600/4000

x=12+9/10

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