1000(6x-10)=40(455+100x)

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Solution for 1000(6x-10)=40(455+100x) equation:



1000(6x-10)=40(455+100x)
We move all terms to the left:
1000(6x-10)-(40(455+100x))=0
We add all the numbers together, and all the variables
1000(6x-10)-(40(100x+455))=0
We multiply parentheses
6000x-(40(100x+455))-10000=0
We calculate terms in parentheses: -(40(100x+455)), so:
40(100x+455)
We multiply parentheses
4000x+18200
Back to the equation:
-(4000x+18200)
We get rid of parentheses
6000x-4000x-18200-10000=0
We add all the numbers together, and all the variables
2000x-28200=0
We move all terms containing x to the left, all other terms to the right
2000x=28200
x=28200/2000
x=14+1/10

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