1000(3x-10)=30(1,280+100x)

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Solution for 1000(3x-10)=30(1,280+100x) equation: 



1000(3x-10)=30(1.280+100x)

We move all terms to the left:

1000(3x-10)-(30(1.280+100x))=0

We add all the numbers together, and all the variables

1000(3x-10)-(30(100x+1.28))=0

We multiply parentheses

3000x-(30(100x+1.28))-10000=0



We calculate terms in parentheses: -(30(100x+1.28)), so:

30(100x+1.28)

We multiply parentheses

3000x+38.4

Back to the equation:

-(3000x+38.4)



We get rid of parentheses

3000x-3000x-38.4-10000=0

We add all the numbers together, and all the variables

-10038.4!=0

There is no solution for this equation

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