100(z-0.2)=-10(5z+.08)

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Solution for 100(z-0.2)=-10(5z+.08) equation: 



100(z-0.2)=-10(5z+.08)

We move all terms to the left:

100(z-0.2)-(-10(5z+.08))=0

We add all the numbers together, and all the variables

100(z-0.2)-(-10(5z+0.08))=0

We multiply parentheses

100z-(-10(5z+0.08))-20=0



We calculate terms in parentheses: -(-10(5z+0.08)), so:

-10(5z+0.08)

We multiply parentheses

-50z-0.8

Back to the equation:

-(-50z-0.8)



We get rid of parentheses

100z+50z+0.8-20=0

We add all the numbers together, and all the variables

150z-19.2=0

We move all terms containing z to the left, all other terms to the right

150z=19.2

z=19.2/150

z=16/125

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