100(6x-10)=40(405+100x)

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Solution for 100(6x-10)=40(405+100x) equation: 



100(6x-10)=40(405+100x)

We move all terms to the left:

100(6x-10)-(40(405+100x))=0

We add all the numbers together, and all the variables

100(6x-10)-(40(100x+405))=0

We multiply parentheses

600x-(40(100x+405))-1000=0



We calculate terms in parentheses: -(40(100x+405)), so:

40(100x+405)

We multiply parentheses

4000x+16200

Back to the equation:

-(4000x+16200)



We get rid of parentheses

600x-4000x-16200-1000=0

We add all the numbers together, and all the variables

-3400x-17200=0

We move all terms containing x to the left, all other terms to the right

-3400x=17200

x=17200/-3400

x=-5+1/17

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