100(3k+1)=2(9k+11)

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Solution for 100(3k+1)=2(9k+11) equation: 



100(3k+1)=2(9k+11)

We move all terms to the left:

100(3k+1)-(2(9k+11))=0

We multiply parentheses

300k-(2(9k+11))+100=0



We calculate terms in parentheses: -(2(9k+11)), so:

2(9k+11)

We multiply parentheses

18k+22

Back to the equation:

-(18k+22)



We get rid of parentheses

300k-18k-22+100=0

We add all the numbers together, and all the variables

282k+78=0

We move all terms containing k to the left, all other terms to the right

282k=-78

k=-78/282

k=-13/47

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