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10/x=9/(x-3)
We move all terms to the left:
10/x-(9/(x-3))=0
Domain of the equation: x!=0
x∈R
Domain of the equation: (x-3))!=0We calculate fractions
x∈R
10x/(-2x^2)+(-(9*x)/(-2x^2)=0
We calculate terms in parentheses: +(-(9*x)/(-2x^2), so:We get rid of parentheses
-(9*x)/(-2x^2
We add all the numbers together, and all the variables
-(+9x)/(-2x^2
We multiply all the terms by the denominator
-(+9x)
We get rid of parentheses
-9x
Back to the equation:
+(-9x)
10x/(-2x^2)-9x=0
We multiply all the terms by the denominator
-9x*(-2x^2)+10x=0
We multiply parentheses
18x^3+10x=0
We do not support expression: x^3
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