10/x=5x/2x+30

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Solution for 10/x=5x/2x+30 equation:



10/x=5x/2x+30
We move all terms to the left:
10/x-(5x/2x+30)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x+30)!=0
x∈R
We get rid of parentheses
10/x-5x/2x-30=0
We calculate fractions
(-5x^2)/2x^2+20x/2x^2-30=0
We multiply all the terms by the denominator
(-5x^2)+20x-30*2x^2=0
Wy multiply elements
(-5x^2)-60x^2+20x=0
We get rid of parentheses
-5x^2-60x^2+20x=0
We add all the numbers together, and all the variables
-65x^2+20x=0
a = -65; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·(-65)·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*-65}=\frac{-40}{-130} =4/13 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*-65}=\frac{0}{-130} =0 $

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