10/x=-7/3x+9

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Solution for 10/x=-7/3x+9 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

10/x = (-7/3)*x+9 // - (-7/3)*x+9

10/x-((-7/3)*x)-9 = 0

(7/3)*x+10/x-9 = 0

7/3*x^1+10*x^-1-9*x^0 = 0

(7/3*x^2-9*x^1+10*x^0)/(x^1) = 0 // * x^2

x^1*(7/3*x^2-9*x^1+10*x^0) = 0

x^1

(7/3)*x^2-9*x+10 = 0

(7/3)*x^2-9*x+10 = 0

DELTA = (-9)^2-(4*10*(7/3))

DELTA = -37/3

DELTA < 0

x in { } 

x belongs to the empty set

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