10/x-5+2x/5-x

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Solution for 10/x-5+2x/5-x equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(2*x)/5-x+10/x-5 = 0

10*x^-1-3/5*x^1-5*x^0 = 0

(10*x^0-3/5*x^2-5*x^1)/(x^1) = 0 // * x^2

x^1*(10*x^0-3/5*x^2-5*x^1) = 0

x^1

(-3/5)*x^2-5*x+10 = 0

(-3/5)*x^2-5*x+10 = 0

DELTA = (-5)^2-(4*10*(-3/5))

DELTA = 49

DELTA > 0

x = (49^(1/2)+5)/(2*(-3/5)) or x = (5-49^(1/2))/(2*(-3/5))

x = -10 or x = 5/3

x in { -10, 5/3}

x in { -10, 5/3 }

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