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10/x-3=3/4x
We move all terms to the left:
10/x-3-(3/4x)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 4x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
10/x-(+3/4x)-3=0
We get rid of parentheses
10/x-3/4x-3=0
We calculate fractions
40x/4x^2+(-3x)/4x^2-3=0
We multiply all the terms by the denominator
40x+(-3x)-3*4x^2=0
Wy multiply elements
-12x^2+40x+(-3x)=0
We get rid of parentheses
-12x^2+40x-3x=0
We add all the numbers together, and all the variables
-12x^2+37x=0
a = -12; b = 37; c = 0;
Δ = b2-4ac
Δ = 372-4·(-12)·0
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1369}=37$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-37}{2*-12}=\frac{-74}{-24} =3+1/12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+37}{2*-12}=\frac{0}{-24} =0 $
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