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10/4x=5/3x-8
We move all terms to the left:
10/4x-(5/3x-8)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 3x-8)!=0We get rid of parentheses
x∈R
10/4x-5/3x+8=0
We calculate fractions
30x/12x^2+(-20x)/12x^2+8=0
We multiply all the terms by the denominator
30x+(-20x)+8*12x^2=0
Wy multiply elements
96x^2+30x+(-20x)=0
We get rid of parentheses
96x^2+30x-20x=0
We add all the numbers together, and all the variables
96x^2+10x=0
a = 96; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·96·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*96}=\frac{-20}{192} =-5/48 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*96}=\frac{0}{192} =0 $
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