10/4=b-2/b

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Solution for 10/4=b-2/b equation:


D( b )

b = 0

b = 0

b = 0

b in (-oo:0) U (0:+oo)

10/4 = b-(2/b) // - b-(2/b)

2/b-b+10/4 = 0

2*b^-1-1*b^1+5/2*b^0 = 0

(5/2*b^1-1*b^2+2*b^0)/(b^1) = 0 // * b^2

b^1*(5/2*b^1-1*b^2+2*b^0) = 0

b^1

(5/2)*b-b^2+2 = 0

(5/2)*b-b^2+2 = 0

DELTA = (5/2)^2-(-1*2*4)

DELTA = 57/4

DELTA > 0

b = ((57/4)^(1/2)-(5/2))/(-1*2) or b = (-(5/2)-(57/4)^(1/2))/(-1*2)

b = ((57/4)^(1/2)-5/2)/(-2) or b = ((57/4)^(1/2)+5/2)/2

b in { ((57/4)^(1/2)-5/2)/(-2), ((57/4)^(1/2)+5/2)/2}

b in { ((57/4)^(1/2)-5/2)/(-2), ((57/4)^(1/2)+5/2)/2 }

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