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10/3x+5/24x+5/2=10/3
We move all terms to the left:
10/3x+5/24x+5/2-(10/3)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 24x!=0We add all the numbers together, and all the variables
x!=0/24
x!=0
x∈R
10/3x+5/24x+5/2-(+10/3)=0
We get rid of parentheses
10/3x+5/24x+5/2-10/3=0
We calculate fractions
2160x^2/864x^2+960x/864x^2+180x/864x^2+(-960x)/864x^2=0
We multiply all the terms by the denominator
2160x^2+960x+180x+(-960x)=0
We add all the numbers together, and all the variables
2160x^2+1140x+(-960x)=0
We get rid of parentheses
2160x^2+1140x-960x=0
We add all the numbers together, and all the variables
2160x^2+180x=0
a = 2160; b = 180; c = 0;
Δ = b2-4ac
Δ = 1802-4·2160·0
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{32400}=180$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(180)-180}{2*2160}=\frac{-360}{4320} =-1/12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(180)+180}{2*2160}=\frac{0}{4320} =0 $
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