10.52=t2+1.39

Solution for 10.52=t2+1.39 equation:

10.52=t2+1.39

We move all terms to the left:

10.52-(t2+1.39)=0

We add all the numbers together, and all the variables

-(+t^2+1.39)+10.52=0

We get rid of parentheses

-t^2-1.39+10.52=0

We add all the numbers together, and all the variables

-1t^2+9.13=0

a = -1; b = 0; c = +9.13;
Δ = b2-4ac
Δ = 02-4·(-1)·9.13
Δ = 36.52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{36.52}}{2*-1}=\frac{0-\sqrt{36.52}}{-2}
=-\frac{\sqrt{}}{-2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{36.52}}{2*-1}=\frac{0+\sqrt{36.52}}{-2}
=\frac{\sqrt{}}{-2}
$