10.5(2-c)=10(2c-4)-6(3c+1)

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Solution for 10.5(2-c)=10(2c-4)-6(3c+1) equation: 



10.5(2-c)=10(2c-4)-6(3c+1)

We move all terms to the left:

10.5(2-c)-(10(2c-4)-6(3c+1))=0

We add all the numbers together, and all the variables

10.5(-1c+2)-(10(2c-4)-6(3c+1))=0

We multiply parentheses

-10.5c-(10(2c-4)-6(3c+1))+21=0



We calculate terms in parentheses: -(10(2c-4)-6(3c+1)), so:

10(2c-4)-6(3c+1)

We multiply parentheses

20c-18c-40-6

We add all the numbers together, and all the variables

2c-46

Back to the equation:

-(2c-46)



We get rid of parentheses

-10.5c-2c+46+21=0

We add all the numbers together, and all the variables

-12.5c+67=0

We move all terms containing c to the left, all other terms to the right

-12.5c=-67

c=-67/-12.5

c=5+1/2.77777777778

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