10-y-z+3y+2z=48

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Solution for 10-y-z+3y+2z=48 equation:


Simplifying
10 + -1y + -1z + 3y + 2z = 48

Reorder the terms:
10 + -1y + 3y + -1z + 2z = 48

Combine like terms: -1y + 3y = 2y
10 + 2y + -1z + 2z = 48

Combine like terms: -1z + 2z = 1z
10 + 2y + 1z = 48

Solving
10 + 2y + 1z = 48

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + 2y + -10 + 1z = 48 + -10

Reorder the terms:
10 + -10 + 2y + 1z = 48 + -10

Combine like terms: 10 + -10 = 0
0 + 2y + 1z = 48 + -10
2y + 1z = 48 + -10

Combine like terms: 48 + -10 = 38
2y + 1z = 38

Add '-1z' to each side of the equation.
2y + 1z + -1z = 38 + -1z

Combine like terms: 1z + -1z = 0
2y + 0 = 38 + -1z
2y = 38 + -1z

Divide each side by '2'.
y = 19 + -0.5z

Simplifying
y = 19 + -0.5z

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