10-p(3p-4)=4(p+1)+9

Solution for 10-p(3p-4)=4(p+1)+9 equation:

10-p(3p-4)=4(p+1)+9

We move all terms to the left:

10-p(3p-4)-(4(p+1)+9)=0

We multiply parentheses

-3p^2+4p-(4(p+1)+9)+10=0


We calculate terms in parentheses: -(4(p+1)+9), so:

4(p+1)+9

We multiply parentheses

4p+4+9

We add all the numbers together, and all the variables

4p+13

Back to the equation:

-(4p+13)


We get rid of parentheses

-3p^2+4p-4p-13+10=0

We add all the numbers together, and all the variables

-3p^2-3=0

a = -3; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·(-3)·(-3)
Δ = -36
Delta is less than zero, so there is no solution for the equation