10-8/3x+3x=1/2x-4

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Solution for 10-8/3x+3x=1/2x-4 equation: 



10-8/3x+3x=1/2x-4

We move all terms to the left:

10-8/3x+3x-(1/2x-4)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 2x-4)!=0

x∈R



We add all the numbers together, and all the variables

3x-8/3x-(1/2x-4)+10=0

We get rid of parentheses

3x-8/3x-1/2x+4+10=0

We calculate fractions


3x+(-16x)/6x^2+(-3x)/6x^2+4+10=0

We add all the numbers together, and all the variables

3x+(-16x)/6x^2+(-3x)/6x^2+14=0

We multiply all the terms by the denominator


3x*6x^2+(-16x)+(-3x)+14*6x^2=0

Wy multiply elements

18x^3+84x^2+(-16x)+(-3x)=0

We get rid of parentheses

18x^3+84x^2-16x-3x=0

We do not support expression: x^3

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