10-7c=10+2(3-5c)

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Solution for 10-7c=10+2(3-5c) equation: 



10-7c=10+2(3-5c)

We move all terms to the left:

10-7c-(10+2(3-5c))=0

We add all the numbers together, and all the variables

-7c-(10+2(-5c+3))+10=0



We calculate terms in parentheses: -(10+2(-5c+3)), so:

10+2(-5c+3)

determiningTheFunctionDomain
2(-5c+3)+10

We multiply parentheses

-10c+6+10

We add all the numbers together, and all the variables

-10c+16

Back to the equation:

-(-10c+16)



We get rid of parentheses

-7c+10c-16+10=0

We add all the numbers together, and all the variables

3c-6=0

We move all terms containing c to the left, all other terms to the right

3c=6

c=6/3

c=2

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