10-5x=3(x-4)-(x+7)

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Solution for 10-5x=3(x-4)-(x+7) equation: 



10-5x=3(x-4)-(x+7)

We move all terms to the left:

10-5x-(3(x-4)-(x+7))=0



We calculate terms in parentheses: -(3(x-4)-(x+7)), so:

3(x-4)-(x+7)

We multiply parentheses

3x-(x+7)-12

We get rid of parentheses

3x-x-7-12

We add all the numbers together, and all the variables

2x-19

Back to the equation:

-(2x-19)



We get rid of parentheses

-5x-2x+19+10=0

We add all the numbers together, and all the variables

-7x+29=0

We move all terms containing x to the left, all other terms to the right

-7x=-29

x=-29/-7

x=4+1/7

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