10-5(x-2)=-3(5x+1)-2

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Solution for 10-5(x-2)=-3(5x+1)-2 equation: 



10-5(x-2)=-3(5x+1)-2

We move all terms to the left:

10-5(x-2)-(-3(5x+1)-2)=0

We multiply parentheses

-5x-(-3(5x+1)-2)+10+10=0



We calculate terms in parentheses: -(-3(5x+1)-2), so:

-3(5x+1)-2

We multiply parentheses

-15x-3-2

We add all the numbers together, and all the variables

-15x-5

Back to the equation:

-(-15x-5)



We add all the numbers together, and all the variables

-5x-(-15x-5)+20=0

We get rid of parentheses

-5x+15x+5+20=0

We add all the numbers together, and all the variables

10x+25=0

We move all terms containing x to the left, all other terms to the right

10x=-25

x=-25/10

x=-2+1/2

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