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10-5(x-11)x=3
We move all terms to the left:
10-5(x-11)x-(3)=0
We add all the numbers together, and all the variables
-5(x-11)x+7=0
We multiply parentheses
-5x^2+55x+7=0
a = -5; b = 55; c = +7;
Δ = b2-4ac
Δ = 552-4·(-5)·7
Δ = 3165
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-\sqrt{3165}}{2*-5}=\frac{-55-\sqrt{3165}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+\sqrt{3165}}{2*-5}=\frac{-55+\sqrt{3165}}{-10} $
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