10-5(c+3)=-4c-3(2c-1)

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Solution for 10-5(c+3)=-4c-3(2c-1) equation: 



10-5(c+3)=-4c-3(2c-1)

We move all terms to the left:

10-5(c+3)-(-4c-3(2c-1))=0

We multiply parentheses

-5c-(-4c-3(2c-1))-15+10=0



We calculate terms in parentheses: -(-4c-3(2c-1)), so:

-4c-3(2c-1)

We multiply parentheses

-4c-6c+3

We add all the numbers together, and all the variables

-10c+3

Back to the equation:

-(-10c+3)



We add all the numbers together, and all the variables

-5c-(-10c+3)-5=0

We get rid of parentheses

-5c+10c-3-5=0

We add all the numbers together, and all the variables

5c-8=0

We move all terms containing c to the left, all other terms to the right

5c=8

c=8/5

c=1+3/5

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