10-4(2x-3)=6x+8-4x

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Solution for 10-4(2x-3)=6x+8-4x equation: 



10-4(2x-3)=6x+8-4x

We move all terms to the left:

10-4(2x-3)-(6x+8-4x)=0

We add all the numbers together, and all the variables

-4(2x-3)-(2x+8)+10=0

We multiply parentheses

-8x-(2x+8)+12+10=0

We get rid of parentheses

-8x-2x-8+12+10=0

We add all the numbers together, and all the variables

-10x+14=0

We move all terms containing x to the left, all other terms to the right

-10x=-14

x=-14/-10

x=1+2/5

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