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10-3x=-x+2410.)6x-4=-2x-52
We move all terms to the left:
10-3x-(-x+2410.)6x-4)=0
We add all the numbers together, and all the variables
-3x-(-1x+2410)6x+10-4)=0
We add all the numbers together, and all the variables
-3x-(-1x+2410)6x=0
We multiply parentheses
6x^2-3x-14460x=0
We add all the numbers together, and all the variables
6x^2-14463x=0
a = 6; b = -14463; c = 0;
Δ = b2-4ac
Δ = -144632-4·6·0
Δ = 209178369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{209178369}=14463$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14463)-14463}{2*6}=\frac{0}{12} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14463)+14463}{2*6}=\frac{28926}{12} =2410+1/2 $
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