10-3(3y+2)=-20

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Solution for 10-3(3y+2)=-20 equation: 



10-3(3y+2)=-20

We move all terms to the left:

10-3(3y+2)-(-20)=0

We add all the numbers together, and all the variables

-3(3y+2)+30=0

We multiply parentheses

-9y-6+30=0

We add all the numbers together, and all the variables

-9y+24=0

We move all terms containing y to the left, all other terms to the right

-9y=-24

y=-24/-9

y=2+2/3

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