10-3(3x-2)=48-5

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Solution for 10-3(3x-2)=48-5 equation: 



10-3(3x-2)=48-5

We move all terms to the left:

10-3(3x-2)-(48-5)=0

We add all the numbers together, and all the variables

-3(3x-2)+10-43=0

We add all the numbers together, and all the variables

-3(3x-2)-33=0

We multiply parentheses

-9x+6-33=0

We add all the numbers together, and all the variables

-9x-27=0

We move all terms containing x to the left, all other terms to the right

-9x=27

x=27/-9

x=-3

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