10-2t+62=t+22

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Solution for 10-2t+62=t+22 equation: 



10-2t+62=t+22

We move all terms to the left:

10-2t+62-(t+22)=0

We add all the numbers together, and all the variables

-2t-(t+22)+72=0

We get rid of parentheses

-2t-t-22+72=0

We add all the numbers together, and all the variables

-3t+50=0

We move all terms containing t to the left, all other terms to the right

-3t=-50

t=-50/-3

t=16+2/3

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