10-2(y-4)=2(y-1)-6y

Solution for 10-2(y-4)=2(y-1)-6y equation:

10-2(y-4)=2(y-1)-6y

We move all terms to the left:

10-2(y-4)-(2(y-1)-6y)=0

We multiply parentheses

-2y-(2(y-1)-6y)+8+10=0


We calculate terms in parentheses: -(2(y-1)-6y), so:

2(y-1)-6y

We add all the numbers together, and all the variables

-6y+2(y-1)

We multiply parentheses

-6y+2y-2

We add all the numbers together, and all the variables

-4y-2

Back to the equation:

-(-4y-2)


We add all the numbers together, and all the variables

-2y-(-4y-2)+18=0

We get rid of parentheses

-2y+4y+2+18=0

We add all the numbers together, and all the variables

2y+20=0

We move all terms containing y to the left, all other terms to the right

2y=-20

y=-20/2

y=-10